strtotime（+1月）和12月/明年的行为

Question

I am working with php and have to compare some data created between the first of the current month and the first of the next month.

I use date('Y-m-d', strtotime('+1 month')); to get the first of the next month. Does this mean that I get the January 1st 2019 when the current date is e.g. 2018-12-16? Or does strtotime('+1 month') just adds the next month and ignores the year, so the result would be 2018-01-16...?

I am not sure, if this is the way strtotime('+1 month') works and I can't test it with a hardcoded month; date('Y-12-d', strtotime('+1 month')); returns 2018-12-28... Did I even test it in the correct way?

Thanks for your help!

Answer 1

strtotime('+1 month') add the 1 month in current month, for example

if current date is 2018-06-28 then

echo date('Y-m-d', strtotime('+1 month'));

Output is :

2018-07-28

If you want first date of month then use :

echo date('Y-m-01', strtotime('+1 month')); // +1 month (Jun to July)

or

echo date('Y-m-01'); // Return Current Month

If current month is December and you add 1 month with strtotime('+1 month') then your date will be in next year