列出两个定义之间的所有日期是同一日期PHP

Question

I have try to list all days between two predefined, when i test on my server i have output like this belowe, as you can see 28.10 is two times there, but when i test this on phptester is back me normal output. What can be problem here? Where i have make mistake?

$from = strtotime('2018-10-25');
$to = strtotime('2018-10-30');
for ($i=$from; $i<=$to; $i+=86400)
    {
         $list[] = date('Y-m-d', $i);
    }
echo '<pre>';
print_r($list);
echo '</pre>';

Output

Array
(
    [0] => 2018-10-25
    [1] => 2018-10-26
    [2] => 2018-10-27
    [3] => 2018-10-28
    [4] => 2018-10-28
    [5] => 2018-10-29
)

Answer 1

I suspect you are running into the end of daylight savings time, when the clock gets set back an hour. So adding 24 hours worth of seconds on that day leaves you on the same day.

It's better to adjust time by days for example using the DateTime class:

$start = new DateTime('2018-10-25');
$end = new DateTime('2018-10-29');
while ($start <= $end) {
    $list[] = $start->format('Y-m-d');
    $start->modify('+1 day');
}
print_r($list);

Output

Array
(
    [0] => 2018-10-25
    [1] => 2018-10-26
    [2] => 2018-10-27
    [3] => 2018-10-28
    [4] => 2018-10-29
)

Demo on 3v4l.org