dsh8009271 2018-12-11 16:33
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如果值为空且低于100,则在codeigniter上进行表单验证

How to validate my form on codeigniter, if the value is empty and below 100.

this is my controller

function aksi_deposit(){
    if ((empty($_POST['deposit']))&& (($_POST['deposit'])<100)) {
        redirect('deposit');
    } else {
        $whc = $this->input->post('deposit');
        $money = $whc * 8000;
        $idUser= 1;
        $b['data'] = $this->m_user->tampil_invoice($idUser);
        $b['coin'] = $money;
        $b['whc'] = $whc;
        $this->load->view('user/v_invoice',$b);
    }
}
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2条回答 默认 最新

  • dongluanguang4774 2018-12-11 17:12
    关注

    i've found the solution, using "OR" it works 100 %.

    if ((empty($_POST['deposit']))OR (($_POST['deposit'])<100)) {
            redirect('deposit');
        } else {
            $whc = $this->input->post('deposit');
            $money = $whc * 8000;
            $idUser= 1;
            $b['data'] = $this->m_user->tampil_invoice($idUser);
            $b['coin'] = $money;
            $b['whc'] = $whc;
            $this->load->view('user/v_invoice',$b);
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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