doty58493 2016-09-23 20:26
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无回声日期空字段

I am currently using php to connect the tables in my ms sql database to appear on my webpage.The table appears however im having issues with the date fields that are null in my sql table.

The table is a garage repair for vehicles.

 create table [VEHICLE_STATUS](
 [STATUS_ID] [int] identity (1,1) not null,
 [VEHICLE_ID] [INT]  not null, 
 [REPAIR_START_DATE] [DATE] not  null,
 [REPAIR_END_DATE] [DATE] not null,
 [DESCRIPTION] [nvarchar] (200) not null
 );

However not all the vehicles are in for repair thus have no repair start or end dates.

I have tried to change the date fields to change to "available" instead of null

The error that comes up is;

Fatal error: Call to a member function format() on null in C:\xampp\htdocs\view.php on line 57

    <?php
            $server = "\SQLEXPRESS";
        $options = array( "Database"=>"test" );


        $conn = sqlsrv_connect( $server, $options );


        if( !$conn ) die( print_r( sqlsrv_errors(), true ) );

$query = "select * from VW_VEHICLE_STATUS";
$sql = sqlsrv_query($conn, $query);


            echo "<table >";
            echo "<tr>";
            echo "<td style='border:1px solid black;Font-size=18;Font-weight=bold'>";
            echo "MAKE";
            echo "</td>";
            echo "<td style='border:1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "MODEL";
            echo "</td>";
            echo "<td style='border:1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "REGISTRATION";
            echo "</td>";
               echo "<td style='border:1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "REPAIR_START_DATE";
            echo "</td>";
               echo "<td style='border:1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "REPAIR_END_DATE";
            echo "</td>";
               echo "<td style='border:1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "DESCRIPTION";
            echo "</td>";
            echo "</tr>
";

           while ($row = sqlsrv_fetch_array($sql)) 
            {
                echo "<tr>";
                echo "<td style='border:1px solid black'>";
                echo $row['MAKE']; 
                echo "</td>";
                echo "<td style='border:1px solid black'>";
                echo $row['MODEL']; 
                echo "</td>";
                echo "<td style='border:1px solid black'>";
                echo $row['REGISTRATION']; 
                echo "</td>";
                     echo "<td style='border:1px solid black'>";
                echo $row['REPAIR_START_DATE']->format("Y-M-d"); 
                echo "</td>";
                     echo "<td style='border:1px solid black'>";
                echo $row['REPAIR_END_DATE']->format("Y-M-d"); ; 
                echo "</td>";
                   echo "<td style='border:1px solid black'>";
                echo $row['DESCRIPTION']; 
                echo "</td>";
                echo "</tr>
";
            }
            echo "</table>";

            sqlsrv_close( $conn);
            ?>
  • 写回答

1条回答 默认 最新

  • dongpigui8898 2016-09-23 20:52
    关注

    Try to check if the value is an instance of DateTime before calling format method on it.

    echo $row['REPAIR_END_DATE'] instanceof DateTime ? $row['REPAIR_END_DATE']->format('Y-m-d') : '';
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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