dongwo5449 2016-08-26 21:40
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使用php合并或更新多维关联数组

I have two arrays.

$all_labels = [
    'data'=> [
        ['label'=> NULL],
        ['label'=> "C1.SNM"],
        ['label'=> "C1.SSM"],
        ['label'=> "C1.TAM"],
        ['label'=> "C1.TIM"],
        ['label'=> "C1.TNM"],
        ['label'=> "C1.TOM"]
    ]
];

$non_complianceData3 = [
    'data'=> [
        ['label'=> "C1.TAM", 'value'=> "1674"],
        ['label'=> "C1.TOM", 'value'=> "574"]
    ]
];

I need the first array to act as the base, i.e. this returns all the labels available from the db. I then need to update the base by using the $non_complianceData3 array data values with the matching labels, in this case the base "C1.TAM" needs to be updated with 'value'=> "1674", and the "C1.TOM" with 'value'=> "574".

How do I go about doing this?

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1条回答 默认 最新

  • dongweishi2028 2016-08-26 21:59
    关注

    If the labels in $all_labels are distinct, it can be done this way:

    // reindex $all_labels['data'] by label
    $all_labels['data'] = array_column($all_labels['data'], null, 'label');
    
    // assign the values from $non_complianceData3['data'] to the new keys
    foreach ($non_complianceData3['data'] as $item) {
        $all_labels['data'][$item['label']] = $item;
    }
    

    If the labels in $all_labels are not distinct, it can be done like this:

    // loop over the items in $non_complianceData3['data']
    foreach ($non_complianceData3['data'] as $item) {
    
        // find all of the matching labels in $all_labels['data'] and replace
        // them with the corresponding $non_complianceData3['data'] items
        foreach ($all_labels['data'] as $key => $value) {
            if ($item['label'] == $value['label']) {
                $all_labels['data'][$key] = $item;
            }
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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