I've downloaded an image uploading script with Ajax from this Link
The codes are:
index.php
<script language="javascript" type="text/javascript">
<!--
function startUpload(){
document.getElementById('f1_upload_process').style.visibility = 'visible';
document.getElementById('f1_upload_form').style.visibility = 'hidden';
return true;
}
function stopUpload(success, str){
var result = '';
if (success == 1){
result = '<span class="msg">The file was uploaded successfully!<\/span><br/><br/>';
}
else {
result = '<span class="emsg">There was an error during file upload!<\/span><br/><br/>';
}
document.getElementById('f1_upload_process').style.visibility = 'hidden';
document.getElementById('f1_upload_form').innerHTML = result + str+'<label>File: <input name="myfile" type="file" size="30" /><\/label><label><input type="submit" name="submitBtn" class="sbtn" value="Upload" /><\/label>';
document.getElementById('f1_upload_form').style.visibility = 'visible';
return true;
}
//-->
</script>
</head>
<body>
<div id="container">
<div id="header"><div id="header_left"></div>
<div id="header_main">Max's AJAX File Uploader</div><div id="header_right"></div></div>
<div id="content">
<form action="upload.php" method="post" enctype="multipart/form-data" target="upload_target" onsubmit="startUpload();" >
<p id="f1_upload_process">Loading...<br/><img src="loader.gif" /><br/></p>
<p id="f1_upload_form" align="center"><br/>
<label>File:
<input name="myfile" type="file" size="30" />
</label>
<label>
<input type="submit" name="submitBtn" class="sbtn" value="Upload" />
</label>
</p>
<iframe id="upload_target" name="upload_target" src="#" style="width:0;height:0;border:0px solid #fff;"></iframe>
</form>
</div>
<div id="footer"><a href="http://www.ajaxf1.com" target="_blank">Powered by AJAX F1</a></div>
</div>
</body>
Uploader.php
<?php
// Edit upload location here
$destination_path = getcwd().DIRECTORY_SEPARATOR;
$result = 0;
$target_path = $destination_path . basename( $_FILES['myfile']['name']);
if(@move_uploaded_file($_FILES['myfile']['tmp_name'], $target_path)) {
$result = 1;
// echo $target_path;
}
sleep(1);
?>
<script language="javascript" type="text/javascript">window.top.window.stopUpload(<?php echo $result.",".$target_path; ?>);</script>
I want to show the url of uploaded image. So that it can be use instantly. I've a little knowledge about ajex. I tried by writing two three of codes but it's not working.
Anyone can help to show the file url. Thanks in advance.