douye1940 2016-06-21 13:47
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如何使用Goutte获取div标签中的所有链接

I am trying to get the all links present inside the div tag. I am able to get all the name but also wants to get the links also. Sample Html:

<li id="u_1y_y" class="friendBrowserListUnit">
<div class="clearfix">
<a class="_8o _8t lfloat _ohe" aria-hidden="true" tabindex="-1" href="/profile.php?id=100004732455685&fref=pymk" role="presentation">
<div class="clearfix _42ef">
<div class="rfloat _ohf">
<div class="friendBrowserContentAlignMiddle">
<div class="friendBrowserNameTitle fsl fwb fcb">
<a href="/profile.php?id=100004732455685&hc_location=friend_browser&fref=pymk">Jeya Kumar</a>
</div>
<div class="friendBrowserMarginTopMini"></div>
<div class="fsm fwn fcg">
</div>
</div>
</div>
</li>
<li id="u_1y_y" class="friendBrowserListUnit">
<div class="clearfix">
<a class="_8o _8t lfloat _ohe" aria-hidden="true" tabindex="-1" href="/profile.php?id=100004732455&fref=pymk" role="presentation">
<div class="clearfix _42ef">
<div class="rfloat _ohf">
<div class="friendBrowserContentAlignMiddle">
<div class="friendBrowserNameTitle fsl fwb fcb">
<a href="/profile.php?id=100004732&hc_location=friend_browser&fref=pymk">Aman Kumar</a>
</div>
<div class="friendBrowserMarginTopMini"></div>
<div class="fsm fwn fcg">
</div>
</div>
</div>
</li>

What I tried:

$message = $crawler->filter('div.friendBrowserNameTitle.fsl.fwb.fcb');
foreach ($message as $key) {
    echo $key->textContent . '<br>';
}

Output:

Jeya Kumar
Aman Kumar

But how to get the links:

/profile.php?id=100004732455685&hc_location=friend_browser&fref=pymk
/profile.php?id=100004732&hc_location=friend_browser&fref=pymk
  • 写回答

1条回答 默认 最新

  • doushang3352 2016-06-23 14:16
    关注

    When a user makes a request using Goutte, a Symfony\Component\DomCrawler instance is returned. The Crawler object provides the Crawler::links() utility method, providing all links within the given crawler object.

    The Crawler::links() method will return an array of links found within.

    $links = $crawler->links();
    foreach ($links as $link) {
        echo $link->getUri();
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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