dte29947 2016-06-08 23:48
浏览 273
已采纳

无法在laravel控制器类中调用类方法

Suppose I have this code:

class UserController extends Controller
{
    protected $test;

    public function __construct()
    {
        $this->test = new Test();

    }

    // first call this func
    public function add_name()
    {
        $this->test->add_name('name1')
        return $this->test->get_name();
    }

    // then this one
    public function show_name()
    {
        return $this->test->get_name();
    }

}

class Test
{
    protected  $name;

    public function get_name()
    {
        return $this->name;
    }

    public function add_name($name)
    {
        $this->name = $name;
    }
}

So when I call show_name() function after add_name() in UserController(first class), return nothing. What is my code problem? (when calling add_name() function it work correctly)

  • 写回答

1条回答 默认 最新

  • duanfan5012 2016-06-09 04:10
    关注

    In Laravel, It's not good practice to write separate class inside the Controller file . You have to create a separate class file in app/Classes directory . say for eg your class, Class_Test.php inside app/class. And in Your Controller file, on the top, you need to include namespace of class . Your controller function should be like .

    use App\Classes\Class_Test;

    class UserController extends Controller {

    public function add_name()
    {
       //call the class function
        Class_Test::add_name('name1');
    }
    
    // then this one
    public function show_name()
    {
        Class_Test::get_name();
    }
    

    }

    Hope this Help you .
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥100 set_link_state
  • ¥15 虚幻5 UE美术毛发渲染
  • ¥15 CVRP 图论 物流运输优化
  • ¥15 Tableau online 嵌入ppt失败
  • ¥100 支付宝网页转账系统不识别账号
  • ¥15 基于单片机的靶位控制系统
  • ¥15 真我手机蓝牙传输进度消息被关闭了,怎么打开?(关键词-消息通知)
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度