douque8855 2016-01-20 19:26
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PHP - 向关联数组添加新的“键值”

I'm trying almost everything to add a new key and its value to a result query.

    $consulta = "SELECT p.id_empleado,count(p.id_empleado) as pendientes,e.nombre,e.apellidos FROM partidas_empleados p ";
    $consulta.= "inner join empleados e on p.id_empleado=e.id_empleado ";
    $consulta.= "WHERE abierta=TRUE group by id_empleado";

    $sql = $con->prepare($consulta);
    $ok = $sql->execute();
    $query = $sql->fetchAll(PDO::FETCH_ASSOC);

    for($i=0;$i<count($query);$i++){
        //echo "hola";
        $fila = $query[$i];
        $consulta = "SELECT id_partida FROM partidas_empleados where id_empleado=? ";
        $sql = $con->prepare($consulta);
        $ok = $sql->execute(array($fila['id_empleado']));
        $sub_query = $sql->fetchAll(PDO::FETCH_ASSOC);
        //echo $sub_query;
        //$fila[]= array("lista_partidas"=>$sub_query);
        $fila['lista_partidas']= $sub_query;
    }

$sub_query is just a list of asociative arrays

I'm trying to add $sub_query to $query with lista_partidas as a key.

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1条回答 默认 最新

  • dongtangxi1584 2016-01-21 07:08
    关注

    As @kunruh and @jeroen said I was creating a copy of and modifying that copy.

        $consulta = "SELECT p.id_empleado,count(p.id_empleado) as pendientes,e.nombre,e.apellidos FROM partidas_empleados p ";
        $consulta.= "inner join empleados e on p.id_empleado=e.id_empleado ";
        $consulta.= "WHERE abierta=TRUE group by id_empleado";
    
        $sql = $con->prepare($consulta);
        $ok = $sql->execute();
        $query = $sql->fetchAll(PDO::FETCH_ASSOC);
    
        for($i=0;$i<count($query);$i++){
            $consulta = "SELECT id_partida FROM partidas_empleados where id_empleado=? ";
            $sql = $con->prepare($consulta);
            $ok = $sql->execute(array($fila['id_empleado']));
            $sub_query = $sql->fetchAll(PDO::FETCH_ASSOC);
            $query[$i]['lista_partidas']= $sub_query;
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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