dongshang1934 2015-10-27 05:11
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仅显示来自多个数组值的单个记录

I am fetching data from an api and i need to fetch data for same value only once.for ex. "Test Storage" is coming 3 times and i need to show it only first record of it and same for walk top and walk middle.This is format of xml array

I am fetching data

SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 1

)
SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 2
)
SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Test Storage
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Middle
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Top
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Top
    [iDefLeaseNum] => 1
)SimpleXMLElement Object
(
    [R_Code] => 1
    [sTypeName] => Walk Middle
    [iDefLeaseNum] => 1
)



  foreach($formatUnits->NewDataSet->Table as $unit)
   {
    echo $unit->iDefLeaseNum;
    echo $unit->sTypeName;
   }
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2条回答 默认 最新

  • doujiao1949 2015-10-27 05:54
    关注

    Store the value and check if it exists before outputting it.

    $arr = array();
    foreach($formatUnits->NewDataSet->Table as $unit){
        if(! isset($arr[$unit->sTypeName]) ){
            $arr[$unit->sTypeName] = $unit->iDefLeaseNum;
            echo $unit->iDefLeaseNum;
            echo $unit->sTypeName;
        }
    }
    
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