使用PHP从XML文件中获取相同的元素但不同的值

Question

I want to fetch image path from bbc news XML file but there are 2 same elements media:thumbnail so when i try to fetch the image , it fetch the first element image URL and its small one .... I want to fetch the 2nd element image URL

<media:thumbnail width="66" height="49" url="http://news.bbcimg.co.uk/media/images/79823000/jpg/_79823050_afpgetty_harry.jpg"/>  
<media:thumbnail width="144" height="81" url="http://news.bbcimg.co.uk/media/images/79823000/jpg/_79823051_afpgetty_harry.jpg"/> 

One method i have tried;

 'img' => $node->getElementsByTagName('thumbnail')->item(0)->getAttribute('url'),
 'img1' => $node->getElementsByTagName('thumbnail')->item(0)->getAttribute('url')

i declared 2 different variables and tried to fetch the URL as i thought i can use the 2nd URL but its not working thanks for helping

Answer 1

$images =  $node->getElementsByTagName('thumbnail');
foreach ($images as $image)
{
    echo $image->getAttribute('url');   
}

Should do the trick