drbmhd9583 2014-12-12 10:47
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用php移动文件

I am trying to upload a client file to my server (from an html form using a "post" method), run a program on the $upldfile variable and then display the program results as downloadable links for the client.

My code is listed below and every time I run this I get the "file upload failed" notice.

Does anyone know if this is to with a permissions based problem or a server error or a code issue?

Thank you all in advance for any help offered

<?php
        error_reporting(E_ALL);
        ini_set('display_errors', 1);

        $destination_path = getcwd().DIRECTORY_SEPARATOR;
        $target_path = $destination_path . "uploads/" . basename( $_FILES["file"{["name"]);
        $upldfile = move_uploaded_file($_FILES['file']['tmp_name'], $target_path);

        if ($upldfile){
            echo "<p>File upload success.</p>";
        } else {
            echo "<p>File upload failed.";
        }
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1条回答 默认 最新

  • dongqidi2799 2014-12-16 09:56
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    ANSWER:

    Changing the permissions appropriately,

    and also

    modifying the php.ini file to allow larger file uploads.

    The code itself in the original file was correct.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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