doushi5913 2015-01-21 15:06
浏览 25
已采纳

通过单击链接显示mySQL条目

I've got one site which should be like a list of contents. The topics are saved in a mySQL database. If you click on a topic it should open a new site. The only difference between those sites is the text which is also saved in that database.

How can I realize that without writing hundreds of sites?

Example:

--page1.php-- --page2.php----- |Topic1 | |Database entry| |Topic2 ----|-Click->|with title | |Topic3 -, | |"Topic2" | ---------|--- ---------------- | Click | \/ --page2.php----- |Database entry| |with title | |"Topic3" | ----------------

If you click "Topic2" page2.php opens containing the Database entry of "Topic2", if you click another topic, the same page opens but it contains a different entry.

Thank you!

  • 写回答

1条回答 默认 最新

  • douwen7905 2015-01-21 15:08
    关注

    You pass the unique identifier of the topic by a GET parameter in the URL.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 52810 尾椎c三个a 写蓝牙地址
  • ¥15 elmos524.33 eeprom的读写问题
  • ¥15 使用Java milo连接Kepserver服务端报错?
  • ¥15 用ADS设计一款的射频功率放大器
  • ¥15 怎么求交点连线的理论解?
  • ¥20 软件开发方法学习来了
  • ¥15 微信小程序商城如何实现多商户收款 平台分润抽成
  • ¥15 HC32L176调试了一个通过TIMER5+DMA驱动WS2812B
  • ¥15 cocos的js代码调用wx.createUseInfoButton问题!
  • ¥15 关于自相关函数法和周期图法实现对随机信号的功率谱估计的matlab程序运行的问题,请各位专家解答!