duanchu0031 2014-12-14 21:38 采纳率: 0%
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PHP如何将URL参数传递到另一个URL

I have a URL with a parameter

www.url.com/page.php?n=name

Now, within a page.php I need to create a hyperlink that works with that parameter. I now have

<a href="page2.php?a=param2&n=<?php $_GET["n"] ?>" >

but this does not work and the URL shows with empty parameter "n":

http://www.url.com/page2.php?a=param2&n=

Could you please help me to pass that parameter in the hyperlink? Kindly thank you in advance.

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  • doulu4413 2014-12-14 21:40
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    You need to do <?php echo $_GET["n"] ?>

    The echo actually prints it into the code. You were just calling it.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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