在json数组中输出Json数组

Question

I'm trying to get an output like this one below. Its combining latitude and longitude into an array inside the object. That is what I'm trying to get mine to do. I'm very new to php and json and have been looking it up for days with no luck. Can php output this from mysql database. If it can, how do you do it.

Desired Json output

[
    {
        "business_name": "Johns Pizza",
        "latlng": [
            99.457434,
            14.349869
        ],
        "business_id": "1"
    },
        {
        "business_name": "Daves Pizza",
        "latlng": [
            19.457434,
            13.349869
        ],
        "business_id": "2"
    },
       {
        "business_name": "Jakes Pizza",
        "latlng": [
            75.457434,
            12.349869
        ],
        "business_id": "3"
    }
] 

Current Json Output

       [{"business_name":"Crush Wine Bar","latlng":"43.6894658949280400,-116.3533687591552700",
"business_id":"2","distance":"23.0298400562551"},{"business_name":"Apple Headquarters","latlng":"37.3324083200000000,-122.0304781500000000",
"business_id":"3","distance":"23.0298400562551"}]

My php file

<?php
if (isset($_GET['lat']) && isset($_GET['lon'])&& isset($_GET['dist'])) {
    //make a simple database connection
    $db = new mysqli();
    $lat = $_GET['lat'];
    $lon = $_GET['lon'];
    $dist = $_GET['dist'];

    $search_sql = "SELECT business_id, business_name, CONCAT_WS(\",\",business_lat, business_lon) AS latlng, ( 3959 * acos( cos( radians(37) ) * cos( radians( " . $lat . " ) ) * cos( radians( " . $lon . " ) - radians(-122) ) + sin( radians(37) ) * sin( radians( " . $lat . " ) ) ) ) AS distance
    FROM business_data HAVING distance < " . $dist . " ORDER BY distance LIMIT 0 , 20";

    $search_results = $db->query($search_sql);

    if($search_results->num_rows) {
        while ($row = $search_results->fetch_assoc()) {
            $return_data[] = array (
                'business_name' => $row['business_name'],
                'latlng'        => $row['latlng'],
                'business_id'   => $row['business_id'],
                'distance'      => $row['distance']
            );
        } //end while
    } else {
        $return_data[] = array();
    }//end if
} else {
    $return_data[] = array();
}

$bd_json = json_encode($return_data);

$db->close();

echo $bd_json;
?>

Answer 1

You can do this something like this:

while ($row = $search_results->fetch_assoc())
{
    $return_data[] = array(
                            'business_name' => $row['business_name'],
                            'latlng'        => explode(',', $row['latlng']),
                            'business_id'   => $row['business_id'],
                            'distance'      => $row['distance']
                            );
}