I am trying to pass image that I took in my mobile device to be saved in my server. the server side is coded in php. here is the javascript code:
var options = new FileUploadOptions();
options.fileKey = "image";
options.fileName = newPlace.id;
options.mimeType="image/jpeg";
var params = new Object();
params.value1 = "test";
params.value2 = "param";
options.params = params;
options.chunkedMode = false;
var ft = new FileTransfer();
ft.upload(cameraImg, "http://www.myserver.com/upload.php", imageUploaded, imageUploadedError, options);
The server side code is:
<?php
if(isset($_FILE['image'])) {
echo "good";
$ourFileName = "good.txt";
$ourFileHandle = fopen($ourFileName, 'w') or die("can't open file");
fclose($ourFileHandle);
$file_name = $_FILE['image']['name'];
$file_tmp = $_FILE['image']['tmp_name'];
move_uploaded_file($file_tmp, 'images/'.$file_name);
}
else {
echo "not good";
}
?>
I know I am connecting to the server and the php code is running but it is not catching the `if(isset($_FILE['image'])). I know this because I am getting an alert that says "response: not good". Where is my mistake? Thanks in advance!
