通过php执行shell命令并在浏览器中显示它？

Question

I would like to execute a shell command through php and display it in a browser. Is there anyway to do so? here is my php code : [test.php]

<?php
$number=$_GET["num"];
$date=$_GET["date"];
$output = shell_exec('egrep -w  '2012-09-01|974' /home/myquery_test/log/push.log');
echo "<pre>$output</pre>";
?>

When I run this(test.php) file from browser nothing shows up. But when i change the

$output = shell_exec('ls')

its working fine!! Why isn't the egrep/grep command not working??

Answer 1

The egrep command isn't working, because you're using single quotes as a string constant delimiter: 'egreep -w' <==> 2012-09-01|974' <==> /home/myquery_test/log/push.log' <==
Just use double quotes in the string, or as string delimiters OR escape the quotes.

shell_exec('egrep -w  \'2012-09-01|974\' /home/myquery_test/log/push.log');
shell_exec('egrep -w  "2012-09-01|974" /home/myquery_test/log/push.log');
shell_exec("egrep -w  '2012-09-01|974' /home/myquery_test/log/push.log");

And, to avoid not getting the warnings and errors that would have brought this issue to light when testing, set your ini to E_STRICT|E_ALL, and fix the warnings, rather then ignoring them. [teasingly: after you're done with that, you might want to consider accepting some answers]I see you've accepted a lot while I was typing this post up :)

Using variables in your command:

$output = shell_exec("tail -f | egrep '$number.*$date' /var/www/myquery_test/log/push.log");
$output = shell_exec('tail -f | egrep "'.$number.'.*'.$date.'" /var/www/myquery_test/log/push.log');
$output = shell_exec("tail -f | egrep \"$number.*$date\" /var/www/myquery_test/log/push.log");