dongmi19720408 2015-04-10 14:15
浏览 18
已采纳

如何使用AJAX将多个值发布到PHP函数?

I have this code:

    var name= "theName";
    var surname= $('#surname').val();
    $.ajax({
        url: 'SaveEdit.php',
        type: 'post',
        data: { "callFunc1": whichOne},
        success: function(response) { 
        alert(response);
        }
    });

It's working, but i need to do something like this:

    var name= "theName";
    var surname= $('#surname').val();
    $.ajax({
        url: 'SaveEdit.php',
        type: 'post',
        data: { "callFunc1": whichOne, name},
        success: function(response) { 
        alert(response);
        }
    });

It gives me errors like:
Warning: missing argument 2 for func1()

I am using this code too:

function func1($data, $name){
    //some code here
}    

if (isset($_POST['callFunc1'])) {
    echo func1($_POST['callFunc1']);
}

How to do it right?

  • 写回答

2条回答 默认 最新

  • dpwtr666638 2015-04-10 14:17
    关注

    Either create an array and pass as much as variable you want. otherwise try this:-

     var name= "theName";
        var surname= $('#surname').val();
        $.ajax({
            url: 'SaveEdit.php',
            type: 'post',
            data: { "callFunc1": whichOne,"callFunc2": name},
            success: function(response) { 
            alert(response);
            }
        });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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