duanjiao3754 2015-07-31 01:43
浏览 83
已采纳

聚合函数不能在mysql中工作

I want to use aggregate function on mysql. I have to use this query.

SELECT COUNT (*) FROM \`pelayanan\` where \`ID_STATUS\` = '1'

But, It doesn`t work. It became error.

1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '*) FROM `pelayanan` where `ID_STATUS` = '1' LIMIT 0, 25' at line 1

It same error for the other aggregate function like sum.

How can I solve this problem?

  • 写回答

1条回答 默认 最新

  • dongqixian8474 2015-07-31 01:47
    关注

    This is your query:

    SELECT COUNT (*)
    FROM pelayanan 
    where ID_STATUS = '1';
    

    It is easier to see the problem when formatted correctly (for Stack Overflow). A space is not allowed after any function, including count(). So:

    SELECT COUNT(*)
    FROM pelayanan 
    WHERE ID_STATUS = '1';
    

    This is explained in a note in the documentation:

    Note

    By default, there must be no whitespace between a function name and the parenthesis following it. This helps the MySQL parser distinguish between function calls and references to tables or columns that happen to have the same name as a function. However, spaces around function arguments are permitted.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 表达式必须是可修改的左值
  • ¥15 如何绘制动力学系统的相图
  • ¥15 对接wps接口实现获取元数据
  • ¥20 给自己本科IT专业毕业的妹m找个实习工作
  • ¥15 用友U8:向一个无法连接的网络尝试了一个套接字操作,如何解决?
  • ¥30 我的代码按理说完成了模型的搭建、训练、验证测试等工作(标签-网络|关键词-变化检测)
  • ¥50 mac mini外接显示器 画质字体模糊
  • ¥15 TLS1.2协议通信解密
  • ¥40 图书信息管理系统程序编写
  • ¥20 Qcustomplot缩小曲线形状问题