合并具有日期索引的相同数组并返回新数组[关闭]

Question

My Array

Array
(
    [1] => Array
        (
            [19-05-18] => 9:00
        )

    [2] => Array
        (
            [19-05-18] => 9:00
        )

    [3] => Array
        (
            [19-05-18] => 9:06
        )

    [4] => Array
        (
            [19-05-18] => 9:10
        )

    [5] => Array
        (
            [19-05-18] => 9:10
        )
    [9] => Array
        (
            [22-05-18] => 18:23
        )

    [10] => Array
        (
            [22-05-18] => 18:25
        )

    [11] => Array
        (
            [22-05-18] => 18:25
        )

    [12] => Array
        (
            [22-05-18] => 18:27
        )

    [13] => Array
        (
            [22-05-18] => 18:27
        )

    [14] => Array
        (
            [22-05-18] => 18:23
        )
)

But I want the output like this

Array
(
    [1] => Array
        (
            [19-05-18] => 9:00
            [19-05-18] => 9:06
            [19-05-18] => 9:10
        )
    [2] => Array
        (
            [22-05-18] => 18:23
            [22-05-18] => 18:25
            [22-05-18] => 18:27
        )
)

Answer 1

$new = array();
foreach ($arr as $val) {
    foreach ($val as $k => $v) {
        if (!isset($new[$k]))
            $new[$k] = array();

        if (!in_array($v, $new[$k])) {
            $new[$k][] = $v;
        }
    }
}

You could have something like this.

It will store the times in an array of arrays with the times as new indexes.
The first if statement will ensure that there are not duplicate entries. Of course, if you want duplicate entries then you are more than welcome to remove that statement from the code.