dongsanhu4784 2014-04-29 13:52
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PHP - Eval()无法正常工作[关闭]

My code isn't working, what am i doing wrong?

Its a very simple and small script

<textarea name="codebtn" id="code"></textarea> 
<input name="code" type="submit" /> 
</form> 
<br> 

Result 
<br> 
<?php 


if(isset($_POST["code"])) { 

$lol = $_POST["codebtn"];

eval('?>' . $lol .'<?php'); 

} 

?>
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2条回答 默认 最新

  • 普通网友 2014-04-29 13:56
    关注

    This has nothing to do with eval, and everything to do with your form.

    Because <input name="code" /> has no value attribute, it is not being sent as part of the request, thereby causing isset($_POST["code"]) to fail.

    Try:

    <input type="submit" name="code" value="lol" />
    

    As an aside, what's wrong with echo $lol instead of eval?

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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