PHP不使用控制结构打印“偶数”或“奇数”

Question

How to check in PHP or JavaScript to display a given digit is EVEN or ODD without using conditional operators or control structures (i.e. without if, for, foreach, do-while, etc)?

For example, If my input is 20 then system should output "EVEN" and for the input 21 output should be "ODD" . Likewise for any numbers.

Any help will be appreciated.

Answer 1

PHP

$vals = ['EVEN','ODD'];
echo $vals[$digit % 2];