dpict99695329 2018-12-24 23:08 采纳率: 100%
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{完成} Mysql查询无法处理php脚本但正在使用PhpMyAdmin

I have this user verification file:

<?php
session_start();
require 'db-D.php';

$email = $_GET['email'];
$code  = $_GET['code'];

$sql  = 'UPDATE `login_D` SET `active`= 1 WHERE email=\"'.$email.'\" and code=\''.$code.'\'';

$conn->query($sql) or $_SESSION['message'] = 'invalid URL' and $_SESSION['details'] = null and header('location: error.php') and die();
header('location: login.php');

?>

I send the user a mail and then use GET method to retrieve the info. The URL looks like this:

192.168.0.101/verifiy.php?email=somemail@mail.com&code=c16c0745def04703e62daa72270c9a89c113a0b208ddd0072b6f828fe1adc81b

The problem is that when I query $sql I get no errors and when I check the active value on PhpMyAdmin it is 0 not 1.

I ran the same script (with the values manually inserted) on PhpMyAdmin and the value changed.

I also looked at the log files (apache and php) and there are no errors.

I am running a LAMP server on a raspberry pi 3.

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2条回答 默认 最新

  • dougua3705 2018-12-25 08:04
    关注

    I found the error:

    $sql  = 'UPDATE `login_D` SET `active`= 1 WHERE email="'.$email.'" and code=\''.$code.'\'';
    

    there were two extra backslashes on email part of the query (the backslashes were taken as text so the query was failing.

    old version:

                                                           <--here-->
    $sql  = 'UPDATE `login_D` SET `active`= 1 WHERE email=\"'.$email.'\" and code=\''.$code.'\'';
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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