Laravel对404的所有例外

Question

the question is simple. Using laravel 5.6

I have for example, this route

Route::get('/services/{id}/{service}', ['as'=> 'services.show', 'uses' => 'ServicesController@show']);

where inside controller I do some fancy logic.

the question is: is there any other elegant way to throw a 404 when something fails inside the controller rather than the typical ErrorException page from laravel? (this is not the 404).

An easy example could be the id is not inserted in the database, so that is making the app fails, not returning a 404.

I guess one solution should be insert a try catch condition and if it fails render(404).. more or less..

Answer 1

Go to app/Exceptions If there is render method change it, or add the method.

Ex:

public function render($request, Exception $exception)
{
    if($exception instanceof NotFoundHttpException){
        return response()->view('errors/404', ['invalid_url'=>true], 404);
    }

    if ($exception instanceof TokenMismatchException && Auth::guest()) {
        error_log('Error :' . $exception->getMessage());
        abort(500);
    }

    if ($exception instanceof TokenMismatchException && getenv('APP_ENV') != 'local') {
        return redirect()->back()->withInput();
    }

    if($exception instanceof \Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException && getenv('APP_ENV') != 'local') {
        error_log('Error :' . $exception->getMessage());
        abort(404);
    }

    if(($exception instanceof PDOException || $exception instanceof QueryException) && getenv('APP_ENV') != 'local') {
        error_log('Error :' . $exception->getMessage());
        abort(500);
    }

    if ($exception instanceof ClientException) {
        error_log('Error :' . $exception->getMessage());
        abort(500);
    }

    return parent::render($request, $exception);
}