duan7264 2014-10-15 21:02
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模板字符串替换在PHP中

I'm trying to build a system where I can create a file based in a template. The template is stored in DB and I populate the template with data sent from a form.

I've tried doing it this way but I can't get to use the array. It always gives me error.

<?php

$string = "test";
$text = "This is a text for testing";

$rplc_string = '{$string}';
$rplc_text = '{$text}';

$tpl = '<html><head><title>{$string}</title></head><body><h1>{$string}</h1><p>{$text}</p><ul><?php foreach($array as $key => $value): ?><li><?php echo $key; ?></li><?php endforeach; ?></ul></body></html>';

$tpl = preg_replace($rplc_string, $string, $tpl);
$tpl = preg_replace($rplc_text, $text, $tpl);

$array = array( 'one' => '1', 'two' => '2', 'three' => '3' );

ob_start();
eval('?>' . $tpl);
$output = ob_get_clean();

echo $output;

?>

Is there better way of doing this?

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2条回答 默认 最新

  • doubu4826 2014-10-15 21:17
    关注

    Replace out double quotes with single quotes when you are defining $tpl

    also the first arg of preg_replace needs to be a regular expression:

    <?php

$string = 'test';
$text = 'This is a text for testing';

$rplc_string = '/{\$string}/';
$rplc_text = '/{\$text}/';


$tpl = '<html><head><title>{$string}</title></head><body><h1>{$string}</h1><p>{$text}</p><ul><?php foreach($array as $key => $value): ?><li><?php echo $key; ?></li><?php endforeach; ?></ul></body></html>';

$array = array( 'one' => '1', 'two' => '2', 'three' => '3' );

$tpl = preg_replace($rplc_string, $string, $tpl);
$tpl = preg_replace($rplc_text, $text, $tpl);

ob_start();
eval('?>' . $tpl);
$output = ob_get_clean();

echo $output;

?>
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