dongti7838 2014-03-30 16:40
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CDbCriteria连接组有错误

I have two table dataset_type and type, now in the type model, I want to create CActiveDataProvider and use CDbCriteria in sql is

 select type.name, type.description , count(dataset_type.dataset_id) as number
 from type ,dataset_type 
 where type.id=dataset_type.type_id 
 group by type.id

How can i write by CDbCriteria

I try to write

$criteria=new CDbCriteria;
$criteria->select='type.name, type.description, count(dataset_type.dataset_id) as number';
$criteria->join='LEFT JOIN dataset_type ON dataset_type.type_id=id';
$criteria->group='type.id';


//$criteria->compare('id',$this->id);
//$criteria->compare('LOWER(name)',strtolower($this->name) , true);
//$criteria->compare('LOWER(description)',strtolower($this->description) , true);

return new CActiveDataProvider($this, array(
    'criteria'=>$criteria,
));

but it shows error

CDbCommand failed to execute the SQL statement: SQLSTATE[42702]: Ambiguous column: 7 ERROR: column reference "id" is ambiguous at character 163. The SQL statement executed was: 

SELECT COUNT(*) 
FROM (SELECT type.name, type.description, count(dataset_type.dataset_id) as number 
FROM "type" "t" 
LEFT JOIN dataset_type ON dataset_type.type_id=id 
GROUP BY type.id) sq
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3条回答 默认 最新

  • douchensi8625 2014-03-30 17:34
    关注

    You should use t.id in following line :-
    $criteria->join='LEFT JOIN dataset_type ON dataset_type.type_id=t.id';
    As t is alias of type table.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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