正则表达式（用于php脚本）

Question

I'm looking for a regex to get from this:

<%image(20100213-na-de-les-mag-hij-even-blijven.jpg|120|120|)%>

to this:

20100213-na-de-les-mag-hij-even-blijven.jpg

Should be really simple but I'm kinda new to regex and been trying for over an hour now. I think the < and % and | are things that regex uses and I have to escape them?

Thank you!

Answer 1

definely this one shall match :

\(([^\|]+)\|

with delimiters :

/\(([^\|]+)\|/