php-function fsockopen（）不起作用

Question

I just started to study php and I'm reading about fsockopen(). I tried to repeat an example from the book, but as result I get an empty page without any information.

<?php
function get_content ($hostname, $path)
{
    $line = "";
    $fp = fsockopen($hostname, 80, $errno, $errstr, 30);
    if(!$fp) echo "$errstr ($errno)<br />
";
    else 
    {
        $headers = "GET $path HTTP/1.0
";
        $headers .= "Host: $hostname
";
        $headers .= "Connection: Close

";
        fwrite($fp, $headers);
        while (!feof($fp))
        {
            $line .= fgets($fp, 1024);
        }
        fclose ($fp);
    }
    return $line;

    $hostname = "www.php.net";
    $path = "/index.php";
    //set_time_limit(180);
    echo get_content ($hostname, $path);
}
?>

What's wrong with this code and why it doesn't work?

Answer 1

Lines after the return statements will never be reached.

You may want to get the last three lines of your function, out of the function.

function get_content($hostname, $path) {
    $line = "";
    $fp   = fsockopen($hostname, 80, $errno, $errstr, 30);
    if (!$fp) echo "$errstr ($errno)<br />
";
    else {
        $headers = "GET $path HTTP/1.0
";
        $headers .= "Host: $hostname
";
        $headers .= "Connection: Close

";
        fwrite($fp, $headers);
        while (!feof($fp)) {
            $line .= fgets($fp, 1024);
        }
        fclose($fp);
    }

    return $line;
}

//Outside the function!
$hostname = "www.php.net";
$path     = "/index.php";
//set_time_limit(180);
echo get_content($hostname, $path);