douxuan0698 2014-01-02 14:25
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已采纳

如果Codeigniter不存在则插入

I am encountering the following problem I am trying to insert data into the table if phone, sushi_service_id both has a row with active = 1 for example:

ID | Phone | sushi_service_id | active
---------------------------------------
1  | 455   | 1                | 1 (LEGAL)
3  | 455   | 1                | 0 (LEGAL)
4  | 455   | 1                | 0 (LEGAL)
5  | 455   | 1                | 1  (NOT LEGAL! HAS THE SAME PHONE+SUSHI_SERVICE_ID+ACTIVE=1)

This is my codeigniter code: how can I improve it in order to work like I said above?

public function add($service, $phone, $sushi_subscription_id, $answer_id, $affiliate_id, $ip, $query, $invite_type, $invite_msg_id)
{

    $this->db->set('service_id', $service->id);
    $this->db->set('sushi_service_id', $service->sushi_service_id);
    $this->db->set('phone', $phone);

    if ($sushi_subscription_id) {
        $this->db->set('sushi_subscription_id', $sushi_subscription_id);
    }

    $this->db->set('answer_id', $answer_id);
    if ($affiliate_id) {
        $this->db->set('affiliate_id', $affiliate_id);
    }

    $this->db->set('added', 'NOW()', FALSE);

    $this->db->set('active', 1);
    $this->db->set('ip', $ip);

    $this->db->set('query', $query);

    if ($invite_type) {
        $this->db->set('invite_type', $invite_type);
    }

    if ($invite_msg_id) {
        $this->db->set('invite_msg_id', $invite_msg_id);
    }

    return ($this->db->insert($this->_table_name)) ? $this->db->insert_id() : FALSE;
}
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2条回答 默认 最新

  • dqlhsm9820 2014-01-02 14:27
    关注

    I would just do a select * from XX where active = 1 and then based on the result of num_rows the insert query.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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