douchunsui2395 2013-10-10 16:54
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PHP - 上传的文件名是EMPTY enctype集

This is my html:

  <form name = "picture" action = "upload.php" method="post" enctype="multipart/form-data">
  <input type="file" name="poza" id = "profilh" onmouseover="profilehov()" onmouseout="profileleave()" onchange="javascript:document.forms['picture'].submit();"></form>

And this is my php:

   $profile = $_POST['poza'];
   if($profile){
   $add = $profile['poza']['name'];
   $userem = $info['email'];
   $allowedExts = array("gif", "jpeg", "jpg", "png");
   $check = explode(".",$add);
   $extension = end($check);
   if((($_FILES['poza']['type']=="image/gif")||($_FILES['poza']['type']=="image/jpeg")||($_FILES['poza']['type']=="image/jpg")||($_FILES['poza']['type']=="image/png") &&($_FILES['poza']['size']<51000))&& in_array($extension,$allowedExts)){
    if(file_exists("uploads/".ENCRYPTION($userem)."/".$add)){
        $errors+=1;
    }
   if($errors == 0){
move_uploaded_file($_FILES['poza']['tmp_name'],"uploads/".ENCRYPTION($userem)."/".$add);
$sql1 = "UPDATE **** SET ****= **** WHERE **** = ****";
$res1 = mysqli_query(****,$sql1) or die (mysqli_error(****));
}
    }
     }

The problem that i have is that the $add variable is empty....why?

P.S: Everything else seems to work fine.

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1条回答 默认 最新

  • doupi1532 2013-10-10 16:56
    关注
    $add = $profile['poza']['name'];
    

    is wrong. Use the $_FILES global:

    $add = $_FILES['poza']['name'];
    

    The name of the file in the form field poza is retrieved.

    Likewise,

    $_FILES['poza']['tmp_name']
    

    is the local filename.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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