doufeixi6014 2012-10-04 02:25
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PHP拆分数组作为参数传递[重复]

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How to pass a variable number of parameters to a function in PHP

I'm trying to dynamically populate parameters when calling a method based on get requests.

For example:

Let's say I have an array with four values:

array(1, 2, 3, 4);

Now I want to pass this to a method that accepts these four parameters. However, this needs to be dynamic, so I can't just do for example method($array[0], array[1], array[2], array[3]).

My question is, how can I take an array with variable lengths and pass it to methods that may also accept varying parameters?

Thank you!

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  • duanshang7007 2012-10-04 02:31
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    You can use call_user_func_array

    function method($arg1, $arg2, $arg3, $arg4){
        echo "$arg1, $arg2, $arg3, $arg4";
    }
    call_user_func_array(method, array(1, 2, 3, 4));//prints 1, 2, 3, 4
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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