mysql和php表单和连接[关闭]

Question

this seems to be correct but I'm missing it somehow.

form in a demo-form.php file

<form action="test.php" method="post" />   
<p>Name: <input type="text" name="name" /></p>
<p>Email: <input type="text" name="email" /></p>
<input type="submit" value="Submit" />
</form>

code in a test.php file

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "forms1";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}

$sql = "INSERT INTO per_Info (name, email)
VALUES ('Test', '[e-mail]')";

if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

The problem: it inserts 'Test', '[e-mail]' into the database (under "name" and "email") instead of whatever name I actually type into the form, in other words, if I type "John" and "[e-mail] in the Name field on the form it will only insert 'Test', '[e-mail]' and not "John", etc.

Answer 1

You post data with a form and that data can be retrieved by using $_POST['inputname']

<?php

    $stmt = $conn->prepare("
       INSERT INTO per_Info
        (name, email) 
       VALUES 
        (?, ?)
    ");

    $stmt->bind_param("ss", $_POST['name'], $_POST['email']);

    if($stmt->execute()){
      echo "New record created successfully";
    }

?>