在地球上选择随机点的更好方法

Question

I am using

$lat=rand(0-pi()*1000000,pi()*1000000)/1000000;
$lon=rand(0-pi()*1000000,pi()*1000000)/1000000;

to pick a random point on earth(in radians) however this method results in points being closer together near polls then near equator since 1 deg of $lon is a smaller distance near the polls then at the equator.

Any ideas on how to get a better distribution?

Answer 1

Based on this article on Wolfram you need something like this:

$long = pi() - 2 * pi() * rand(0, 1000000) / 1000000;
$lat = pi() / 2 - acos(2 * rand(0, 1000000) / 1000000 - 1);