dsfs21312 2016-11-18 06:15
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如何使用preg_replace替换JSON值? [重复]

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This is my JSON file sample.json

{
  "lbl_name":"Your name",
  "dynamic_name":"Hi, {{ name 1 }}, {{ name 2 }} and {{ name 3 }}"
}

and

$content = file_get_contents(sample.json);
$translate = json_decode$content, true);
$replaceContent = preg_replace('/\{{[^)]*\}}/', '%s', $translate);
print_r($replaceContent);

I am getting result

Array ( [lbl_name] => Your name [dynamic_name] => Hi %s ) 

I want result should be

Array ( [lbl_name] => Your name [dynamic_name] => Hi %s, %s and %s ) 

Thanks

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2条回答 默认 最新

  • dongyu6276 2016-11-18 06:23
    关注

    your regex is greedy, therefore trying to match the biggest match it can get.

    use the ?-control character to make your pattern non-greedy, meaning it matches the smallest match it can get:

    $data = "Hi, {{ name 1 }}, {{ name 2 }} and {{ name 3 }}"
    echo preg_replace('/{{[^)]*?}}/', '%s', $data);
    //prints Hi, %s, %s and %s
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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