doubipeng1336 2017-09-03 18:23
浏览 100
已采纳

PHP / PDO查询后大于或等于运算符[重复]

This question already has an answer here:

I'm currently implementing a follow system using PHP and PDO. The code determines if the button "Follow" or "Unfollow" should show based on the inserted data. The database is updating correctly but for some reason the greater than or equal to operator is not working properly, or I'm not querying the database properly. (Not sure which) Anyone know what I'm doing wrong?

In followon.php:

if($row['userID']  && $row['userName']){
    if($row['userID']!=$user_id){
        $follow_userid = $row['userID'];

        $stmt = $user_follow->runQuery("SELECT id FROM following WHERE user1_id=':user_id' AND user2_id=':follow_userid'");
                $stmt->execute(array(":user_id"=>$user_id,":follow_userid"=>$follow_userid));
                $follow = $stmt->fetch(PDO::FETCH_ASSOC);

                if(!$follow >= 1){

            $stmt = $user_follow->runQuery("INSERT INTO following(user1_id, user2_id) VALUES (?, ?)");
                $stmt->bindValue(1,$user_id);
                $stmt->bindValue(2,$follow_userid);
                $stmt->execute();

            $stmt = $user_follow->runQuery("UPDATE tbl_users SET following = following + 1 WHERE userID = ?");
                $stmt->bindValue(1,$user_id);
                $stmt->execute();

            $stmt = $user_follow->runQuery("UPDATE tbl_users SET followers = followers + 1 WHERE userID = ?");
                $stmt->bindValue(1,$follow_userid);
                $stmt->execute();

                }

        header("Location: index.php?id=".$currentID);
      }
}

In followoff.php:

if($row['userID']  && $row['userName']){
    if($row['userID']!=$user_id){
        $unfollow_userid = $row['userID'];

        $stmt = $user_unfollow->runQuery("SELECT id FROM following WHERE user1_id=':user_id' AND user2_id=':unfollow_userid'");
                $stmt->execute(array(":user_id"=>$user_id,":unfollow_userid"=>$unfollow_userid));
                $follow = $stmt->fetch(PDO::FETCH_ASSOC);

                if($follow >= 1){

            $stmt = $user_unfollow->runQuery("DELETE FROM following WHERE user1_id= ? AND user2_id= ?");
                $stmt->bindValue(1,$user_id);
                $stmt->bindValue(2,$unfollow_userid);
                $stmt->execute();

            $stmt = $user_unfollow->runQuery("UPDATE tbl_users SET following = following - 1 WHERE userID = ?");
                $stmt->bindValue(1,$user_id);
                $stmt->execute();

            $stmt = $user_unfollow->runQuery("UPDATE tbl_users SET followers = followers - 1 WHERE userID = ?");
                $stmt->bindValue(1,$unfollow_userid);
                $stmt->execute();

                }

        header("Location: index.php?id=".$currentID);
      }
}

And in index.php (where button appears):

if($user_id){
                if($user_id!=$id){

                    $query2 = $user_home->runQuery("SELECT id FROM following WHERE user1_id=':user_id' AND user2_id=':id'");
                                        $query2->execute(array(":user_id"=>$user_id,":id"=>$id));
                                        $query2result = $query2->fetch(PDO::FETCH_ASSOC);

                    if($query2result >= 1){
                                                echo "<a href='followoff.php?id=$currentID' class='btn btn-default btn-xs'>Unfollow</a>";

                    }
                    else{

                        echo "<a href='followon.php?id=$currentID' class='btn btn-info btn-xs'>Follow</a>";

                    }
                }
            }
</div>
  • 写回答

1条回答 默认 最新

  • doushi5752 2017-09-03 18:31
    关注

    Your trying to test the result set with an ID, $query2->fetch returns an associative array.

    You need to access the field in the result set...

    if($query2result['id'] >= 1){
    

    If you just want to say if a row has not been returned, it will return false.

    if($query2result !== false){
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 CVRP 图论 物流运输优化
  • ¥15 Tableau online 嵌入ppt失败
  • ¥100 支付宝网页转账系统不识别账号
  • ¥15 基于单片机的靶位控制系统
  • ¥15 真我手机蓝牙传输进度消息被关闭了,怎么打开?(关键词-消息通知)
  • ¥15 下图接收小电路,谁知道原理
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度
  • ¥30 关于#r语言#的问题:如何对R语言中mfgarch包中构建的garch-midas模型进行样本内长期波动率预测和样本外长期波动率预测