drcigvoy48900 2018-09-15 17:39
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为什么我不能从服务器变量创建PHP头?

For some reason, I can't include a custom PHP $server variable inside of a header function. PHP doesn't acknowledge it's existence even though I can print it to console. Here are the steps I'm taking.

I have a header in my response which I fetch with

 $domain = $_SERVER["HTTP_X_REQUESTED_DOMAIN"];
 // print_r($domain);
 // prints: stackoverflow.com

Next, I join the $domain variable with 'https://' and create a header.

 $var = 'https://' . $domain;
 header("Access-Control-Allow-Origin: " . $var);

However - I get a console error saying:

The 'Access-Control-Allow-Origin' header contains the invalid value 'https://'.

It's like the $domain variable is empty even though it's set and can be printed to console. If I change the domain variable to a string like 'stackoverflow.com' then everything works perfectly.

 $domain = 'stackoverflow.com'. 

I don't understand what could be the issue if both possibilities of the $domain variable return strings, are not empty, encoded with ASCII and print to screen if I run a print_r() function with them.

Any clues on what to troubleshoot?

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  • donglun4682 2018-09-15 19:34
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    Try adding quotes

     header("Access-Control-Allow-Origin: " ."'". $var ."'");
    
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