douchu4048 2015-05-13 13:03
浏览 17
已采纳

PHP语句没有评估我期望的[重复]

This question already has an answer here:

I have the following code:

<?php

$starting_id = 0;

$params = array ('val' => $starting_id);

echo parse_params ($params);

function parse_params ($params)
{
    $query = ' WHERE ';
    if ($params['val'] === NULL) {
        $query .= ' IS NULL';
        return $query;
    }
    if ($params['val'] == 'NOT NULL') {
        $query .= ' IS NOT NULL';
        return $query;
    }    
    return $query.' = '.$params['val'];
} 

When I run it, I expect to see this:

WHERE 

instead, I get the following:

WHERE IS NOT NULL

Any ideas why?

</div>
  • 写回答

1条回答 默认 最新

  • dsa99349 2015-05-13 13:14
    关注

    According to the PHP type comparison tables,

    $var = 0 ; // (int)
    

    if you compare $var == "string",

    it will return true, you need to type check for this

    $var === "string"
    

    check php type comparison

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 单片机学习顺序问题!!
  • ¥15 ikuai客户端多拨vpn,重启总是有个别重拨不上
  • ¥20 关于#anlogic#sdram#的问题,如何解决?(关键词-performance)
  • ¥15 相敏解调 matlab
  • ¥15 求lingo代码和思路
  • ¥15 公交车和无人机协同运输
  • ¥15 stm32代码移植没反应
  • ¥15 matlab基于pde算法图像修复,为什么只能对示例图像有效
  • ¥100 连续两帧图像高速减法
  • ¥15 如何绘制动力学系统的相图