dongpin3794 2017-11-24 14:42
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使用Curly Braces构造输出字符串 - PHP

When i do either of the two sets of code below i get an parse error and the resulting output doesn't show.

Surely there is a way of assigning a value to a variable, creating another variable to output the string, and then echo the variable (using the curly braces{} syntax)?

First Example

$name = "Jim ";
$show = echo "{$name}is my name";
echo $show;

Second Example

$name = "Jim ";
$show = echo "{$name}is my name";

Neither of the above work?

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1条回答 默认 最新

  • dr2898 2017-11-24 14:46
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    The problem is your setting a variable equal to echo:

    $show = echo"{$name}is my name";

    This should work:

    $name = "Jim ";
    $show = "{$name}is my name";
    echo $show;
    

    Check here for a working example:

    https://ideone.com/ZWDArz

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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