如何从数组内的值中修剪数据？

Question

This is my data:

$d = $request->request->get('data');

The output:

[{"name":"form[id]","value":"10"},{"name":"form[name]","value":"Telefon2"},{"name":"form[uuid]","value":"bb80878ad4"},{"name":"form[productgroup]","value":"6"},{"name":"form[category]","value":"1"},{"name":"form[documents]","value":"7"}

I want to create a new array, that is removing extracting the variable inside the brackets.

 function trim($d) {
          preg_match('#\[(.*?)\]#', $d, $match);
          return $match[1];
   }


$dData = array_combine(array_column(trim($d), 'name'), array_column($d, 'value'));
$json = json_encode($dData);

But the error is

Warning: preg_match() expects parameter 2 to be string, array given

Answer 1

You're going to need to do a few things before you begin.

Firstly, rename the trim function to something like extract_name because PHP already has a built in trim function that removes whitespace from a string - or any character present in the character mask.
Secondly, you are going to need to iterate over each of the elements in the name column. You will notice the error you are getting from preg_match is because you are passing all values in one go.
Thirdly, I am assuming that the value of $d is an array of PHP objects. This is done, and assumed, in my solution using $d = json_decode($d);.

Using array_map instead of a foreach means we can have a nice one liner:

function extract_name($d) {
    preg_match('#\[(.*?)\]#', $d, $match);
    return $match[1];
}

$dData = array_combine(array_map('extract_name', array_column($d, 'name')), array_column($d, 'value'));

The output being:

array:6 [
  "id" => "10"
  "name" => "Telefon2"
  "uuid" => "bb80878ad4"
  "productgroup" => "6"
  "category" => "1"
  "documents" => "7"
]

Live demo