douhu1990 2018-11-02 19:06
浏览 58
已采纳

PHP如何迭代mysqli查询结果?

I'm learning to interact with a database in PHP. The code below works, but I do not understand how the loop iterates through $result.

<?php
  require_once('./login.php');
  $conn = new mysqli($hn, $un, $pw, $db);
  if ($conn->connect_error) die("DIED: CONNECTION FAILED.");

  $query= "SELECT * FROM table1";
  $result = $conn->query($query);
  if (!$result) die("DIED: QUERY FAILED.");

  while ($row = $result->fetch_array(MYSQLI_ASSOC)) {
    $who = $row['WHO'];
    $what = $row['WHAT'];

    echo <<<_END
    WHO: $who<br>
    WHAT: $what<br>
_END;
  }

  $result->close();
  $conn->close();
?>

I understand that while a $result element is available, it will be assigned to $row and processed in the loop. But how does the interpreter know to move to the next $result element?

The code even works when using a for loop instead, such as...

$row_count = $result->num_rows;
for($j = 0; $j < $row_count; $j++) {
  $row = $result -> fetch_array(MYSQLI_ASSOC);

My question boils down to this: how does the interpreter know to use the next element in $result without needing something like $result[$j]?

  • 写回答

1条回答 默认 最新

  • dongya1875 2018-11-02 19:12
    关注

    The query returns a mysqli_result. Per the docs, this object is iterable http://php.net/manual/en/class.mysqli-result.php. So every time you call fetch_array(), the result object it is keeping track of which row it is currently on and returning the appropriate result, then moving forward one element in the result set. When there are no more results left, the function returns null which is evaluated as false thus terminating the loop.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥30 eclipse开启服务后,网页无法打开
  • ¥30 雷达辐射源信号参考模型
  • ¥15 html+css+js如何实现这样子的效果?
  • ¥15 STM32单片机自主设计
  • ¥15 如何在node.js中或者java中给wav格式的音频编码成sil格式呢
  • ¥15 不小心不正规的开发公司导致不给我们y码,
  • ¥15 我的代码无法在vc++中运行呀,错误很多
  • ¥50 求一个win系统下运行的可自动抓取arm64架构deb安装包和其依赖包的软件。
  • ¥60 fail to initialize keyboard hotkeys through kernel.0000000000
  • ¥30 ppOCRLabel导出识别结果失败