正则表达式分裂字符串，如果它包含wordS或单词[关闭]

Question

Edit again to trying to make it more clear.

Wich php regex pattern will give me a match array containing always 2 values wich is the 2 part of a string splitted by the "wordA" or "wordB". If the string do not containt those word, simply return the string as the first array an null in the second array.

Exemple:

preg_match("pattern","foo wordA bar",$match), $match will contain array['foo', 'bar']
preg_match("pattern","foo wordB bar",$match), $match will contain array['foo', 'bar']
preg_match("pattern","foo bar test",$match), $match will contain array['foo bar test', null]

I know that $match first value is always the string so I just don't write it.

OLD question:

I need to split a one line address into part. I can't find a way to capture street part but dont include the APP or APT word if present and if present, capture the words after it.

For exemple:

"5847A, rue Principal APP A" should match: (5847, A, rue Principal,A)

"5847A, rue Prince Arthur APT 22" should match: (5847, A, rue Prince Arthur, 22)

"1111, Sherwood street" should match: (1111, , Sherwood street, )

I'm using PHP.

What I have so far is: /^(\d+)(.*), (.*)(?:APP|APT)(?:\s*(.*))?$/i wich wook with exemple 1 and 2. If I try to make the alternative (APP|APT) optionnal by adding an ? after it, then the third match include the word APP or APT...

Any idea how to exclude the optionnal and alternative APP or APT word from match?

Thank you

EDIT:

I can simplify the problem: How can I regex a string so the match return the same string minus the word APP or APT if he is present in the middle of it.

Answer 1

As @MadaraUchiha pointed out, it's a bad idea to run a regex on an address since they can be in any format.

If you know you have consistent addresses, then I guess you can use the regex:

^([0-9]+)([A-Z])?,\s(?:(.*?)\s(?:APP|APT)\s(.*)|(.*))$

And the replace:

$1,$2,$3$5,$4

Here's how it's performing.

It's pretty similar to yours (I changed few things) and added an or (|) operator to address the second type of addresses without APP or APT.

If you want consistent number of matches, maybe this?

^([0-9]*)([A-Z]?),((?:(?!\sAPP|\sAPT).)*)(?:\sAPP|\sAPT)?(.*)$

Regex101 example.