php check name包含字符串和checkout更多名称

Question

I made a simple function to check if array strings contain a certain name. However, since the names are getting more and more, I have to duplicate elseif all the time. If someone could help me to improve me function please? I'd like to check $arr names.

if the array looks like $arr = array('PDF', 'PSD', 'PNG', 'GIF', 'Mp3', 'JPG'....);

$i can be counted from mysql

 function checkname($arr, $name1, $name2, $name3......... ){
        if (strpos($arr, $name1) !== false) {
            return $name1;
        }elseif(strpos($arr, $name2) !== false){
            return $name2;

        ..............


        }else{
            return ' ';
        }
    }


checkname($arr[$i], 'PDF', 'PSD', 'PNG'........);

Answer 1

May I suggest array_slice() and func_get_args() to solve your argument problem?

<?php
    function checkname($arr, $name) {
        foreach (array_slice(func_get_args(), 1) as $name) {
            if (strpos($arr, $name) !== false) {
                return $name;
            }
        }

        return '';
    }
?>

..alternately, to solve it into infinity (or however many array values your memory can handle) why not pass an array, and simply do the following:

<?php
    function checkname($arr, $names) {
        foreach ($names as $name) {
            if (strpos($arr, $name) !== false) {
                return $name;
            }
        }

        return '';
    }

    checkname($arr[$i], array('PDF', 'PSD', 'PNG'));
?>

Note:

Your current code checks for the position of PDF, PSD, PNG etc., anywhere in your name (in uppercase!!), so MYPNG.PHP would go through fine, and doge.png would fail.