duanfei8149 2018-12-11 21:35
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试图使用存储在单元格数据中的变量

I am facing a problem that doesn't allow variables retrieved from cell data to appear as the declared variable on my web page. I will post an example below ;

email.db - Below represents the cell data for column email_body

email_body = Hi, $name

$name = $row['name'];    

$messagebody = $row["email_body"];

$message = "
            <html>
            <body>
            <p>".$messagebody."</p>
            </body>
            </html>
            ;
            "

As you can see I'm attempting to make $row['name'] appear within $messagebody (which is text stored in a DB). The issue i'm having is that the above code will display $messagebody, but the $name variable will display as plain text and will ignore the variable.

Your help is appreciated,

Thanks.

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  • dongnang8192 2018-12-11 21:44
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    Daniel - I think you might not have the exact right idea about how variables are rendered inside of PHP strings.

    However, there is a function called sprintf that might be the tool to do what you're attempting to do!

    sprintf (string $format [, mixed $... ])

    The first $format argument in your case would be 'Hi, %s' - the %s being a stand-in for another string, $name. The function would then return 'Hi, Bobby', were $name set to bobby. (And name was passed as the second arg.)

    // Re-set the data inside of `email_body` to 'Hi, %s';
// "%s" is a placeholder that hints that a string should be placed there

$name        = $row['name'];
$messagebody = sprintf($row["email_body"], $name);
$message     = "<html>
                  <body>
                    <p>".$messagebody."</p>
                  </body>
                </html>";
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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