dounuo9921 2018-09-07 05:38
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获得某个月的最后一天在31天的月份失败

I have a problem like this. For a given date I need to get the last day of each of the previous months up to 5 months. As an example, if the input date is 2018-08-21, then the result I want is something like (2018-07-31,2018-06-30,2018-05-31,2018-04-30,2018-03-31)

I wrote a for loop to iterate for 5 times and used the following code to get the previous month. But at months of 31 days, it doesn't exactly give the previous month. It gives the last day as "2011-07-31" which is not true. Is there a workaround for this one??

$datetocheck = "2011-07-31";
$lastday = date('Y-m-t', strtotime('-1 month', strtotime($datetocheck)));
echo $lastday; //this gives 2011-07-31(Expected value is 2011-06-30)
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  • donglu7816 2018-09-07 05:56
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    Simple and easy to understand. Try this :-

    $initialDate = "2011-07-31";
    for($i=1; $i<=5; $i++) {
        echo date('Y-m-d', strtotime('last day of -' . $i . ' month', strtotime($initialDate))) . "<br>";
    }
    

    Check this Fiddle link

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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