dongliqin6939 2015-04-06 23:19
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CodeIgniter 3 html helper ul函数,如何将参数传递给li的

I am implementing a site with CodeIgniter 3 and I am using the HTML helper which works fine for what I need. I have the following arrays for my UL

$links = array(
    anchor(index_page(),"Home",(uri_string() == "" ? array('class' => 'active') : '')),
    anchor("about-us","About Us",(uri_string() == "about-us" ? array('class' => 'active') : '')),
    anchor("customers","Customers",(uri_string() == "customers" ? array('class' => 'active') : '')),
    anchor("policy","Policy",(uri_string() == "policy" ? array('class' => 'active') : '')),
    anchor("contact","Contact",(uri_string() == "contact" ? array('class' => 'active') : ''))
);

$attributes_normal = array(
    'id'    => 'main_menu'
);

So, after having those arrays I initialize my ul like this:

<?php echo ul($links, $attributes_normal); ?>

The result is as follows (about us section open for the example):

<ul id="main_menu">
    <li><a href="http://mysitesurl/">Home</a></li>
    <li><a href="http://mysitesurl/about-us" class="active">About Us</a></li>
    <li><a href="http://mysitesurl/customers">Customers</a></li>
    <li><a href="http://mysitesurl/policy">Policy</a></li>
    <li><a href="http://mysitesurl/contact">Contact</a></li>
</ul>

The only question I have here, is there any way to pass the active link condition to the <li> element. I am using Zurb Foundation 5 and by default it adds the class="active" to the <li> element, so I want to use the default CSS.

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  • duandeng2265 2015-04-06 23:50
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    Not without overriding the default _list helper function. On line 145 in the source code for HTML Helper you can see that '<li>' is hardcoded and does not accept additional arguments:

    $out .= str_repeat(' ', $depth + 2).'<li>';
    

    I would probably just set the active class using jQuery or JavaScript, but you could also opt to override the default helper functions for generating lists (see Extending Helpers).

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