Ifelse unix时间戳

Question

Ok here is my issue I tried to use a Ternary operator and a switch break on my issue and still coming up with the same results.

Now Iam trying an ifelse to see if this works but Iam still getting the same error where it should be echoing out "is a P4" but instead it's stating that this is a P1

<?php
//************************************
//https://stackoverflow.com/questions/53180920/unix-time-stamp-adding-  2-weeks-4-weeks-6-weeks-8-weeks/53181428#53181428
//unix time stamp 
//************************************
//1536079080 = 04-09-2018 (Day of the task)
//1541376000 = 11-06-2018 (todays date )
//1542758400 = 11-21-2018 (2 weeks and 1)
//************************************
// > Greater than
// < Less than 
// >=   Greater than or equal to
// <=   Less than or equal to
//************************************

$mod = 1536079080; //unix time stamp 
$moDate = new DateTime('@'. $mod, new   DateTimeZone('America/Los_Angeles')); //Unix change to PST time 
$today = date("d/m/Y"); //todays date


$twoWeeks = time() + (3600*24*14);  //NOW + ( 3600 sec = 1 hour * 24       hours/day * 14 days)
$fourWeeks= time() + (3600*24*28);
$sixWeeks = time() + (3600*24*42);
$eightWeeks = time() + (3600*24*56);


// Less than or equal to and less than
$p1 = ($mod <= $twoWeeks && $mod < $fourWeeks)? true : false;
$res1 = ($p1) ? 'Is a P1' : 'Is not a P1'."<br>";

//Greater than or equal to and less then  6 weeks
$p2 = ($mod >= $fourWeeks && $mod < $sixWeeks)? true : false;
$res2 = ($p2) ? 'is a P2' : 'Is not a P2'."<br>";

//Greater than or equal to and less then 8 weeks
$p3 = ($mod >= $sixWeeks && $mod < $eightWeeks)? true : false;
$res3 = ($p3) ? 'Is a P3' : 'Is not a P3'."<br>";

// is equal to 8 weeks and greater then 8 weeks
$p4 = ($mod == $eightWeeks && $mode > $eightWeeks)? true : false;
$res4 = ($p4) ? 'Is a P4' : 'Is not a P4'."<br>";




echo $res1 , $res2, $res3, $res4;

//Output
//Is a P1
//Is not a P2
//Is not a P3
//Is not a P4

?>

Answer 1

I feel a bit like understanding and doing your home work ;-) but here is a feasible solution, I think...

$mod = 1546079080; //unix time stamp
$moDate = new DateTime('@'. $mod, new   DateTimeZone('America/Los_Angeles')); 
//Unix change to PST time
$today = date("d/m/Y"); //todays date
echo $mod . "<br>";

$twoWeeks = time() + (3600*24*14);  //NOW + ( 3600 sec = 1 hour * 24       hours/day * 14 days)
$fourWeeks= time() + (3600*24*28);
$sixWeeks = time() + (3600*24*42);
$eightWeeks = time() + (3600*24*56);


// Period 1 between 2 and 4 weeks from now
$p1 = ($mod == $twoWeeks && $mod < $fourWeeks)? true : false;
$res1 = ($p1 ? 'Is a P1' : 'Is not a P1')."<br>";

// Period 2 between 4 and 6 weeks from now
$p2 = ($mod >= $fourWeeks && $mod < $sixWeeks)? true : false;
$res2 = ($p2 ? 'is a P2' : 'Is not a P2')."<br>";

// Period 3 between 6 and 8 weeks from now
$p3 = ($mod >= $sixWeeks && $mod < $eightWeeks)? true : false;
$res3 = ($p3 ? 'Is a P3' : 'Is not a P3')."<br>";

// Period 4 more than 8 weeks in future
$p4 = ($mod >= $eightWeeks) ? true : false;
$res4 = ($p4 ? 'Is a P4' : 'Is not a P4')."<br>";

echo $twoWeeks .'<br>'. $fourWeeks .'<br>'.  $sixWeeks .'<br>'. $eightWeeks .'<br><br>' ;
echo $res1 , $res2, $res3, $res4;

// Output
// 1546079080
// 1543432972
// 1544642572
// 1545852172
// 1547061772
// 
// Is not a P1
// Is not a P2
// Is a P3
// Is not a P4