doukundong9652 2014-08-08 13:38
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Laravel:将路由参数传递给filter参数

I have this route (note the filter which is being applied with an optional parameter):

Route::get('/greet/{name?}', array(
    'before'    => 'summergreet:optionalNameToCapture',
    function ($name = 'friend') {
        return View::make('greetview', array('name' => $name));
    }
));

And the assigned filter:

Route::filter('summergreet', function($route, $request, $name = 'amigo')
{
    if (date('m') >= 7 && date('m') <= 9) {
        return View::make('summergreetview', array('name' => $name));
    }
});

How can I capture the optional parameter to the route and pass it through to the filter?

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1条回答 默认 最新

  • drwxg62286 2014-08-08 13:40
    关注

    You can do

    Route::filter('summergreet', function($route, $request, $name = 'amigo')
    {
        $name = $route->parameter('name');
        if (date('m') >= 7 && date('m') <= 9) {
            return View::make('summergreetview', array('name' => $name));
        }
    });
    

    I'm not sure how it works for 'optional' parameters. You might need to check isset() or is_null on the variable first....

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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