doubi4814 2017-09-03 19:28
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if($ _ SERVER ['REQUEST_METHOD'] =='POST')无效。 数据未从数据库中检索[关闭]

I have created a login page in Android. The first user will register and then he will redirect to the login page where he has to enter these details as name and id. Plus this name & id will get display on another android activity. The issue is user registration is doing correctly. but while retriving this name & id it gives me error"{"status":"false","message":"Error occured, please try again!"}" Please let me know if I have done something wrong. I am using this with an android file. where these name & id will get displayed.

Code:

abc.php
<?php

   if($_SERVER['REQUEST_METHOD']=='POST'){
  // echo $_SERVER["DOCUMENT_ROOT"];  // /home1/demonuts/public_html
//including the database connection file
       include_once("dbConfig.php");

       $mi_id = isset($_POST['mi_id']) ? $_POST['mi_id'] : null;
      $name = isset($_POST['name']) ? $_POST['name'] : null;

     if( $mi_id == '' || $name == '' ){
            echo json_encode(array( "status" => "false","message" => "Parameter missing!") );
     }else{
        $query= "SELECT * FROM registerdemo WHERE mi_id='$mi_id' AND name='$name'";
            $result= mysqli_query($con, $query);

            if(mysqli_num_rows($result) > 0){  
             $query= "SELECT * FROM registerdemo WHERE mi_id='$mi_id' AND name='$name'";
                         $result= mysqli_query($con, $query);
                     $emparray = array();
                         if(mysqli_num_rows($result) > 0){  
                         while ($row = mysqli_fetch_assoc($result)!=NULL) {
                                     $emparray[] = $row;
                                   }
                         }
               echo json_encode(array( "status" => "true","message" => "Login successfully!", "data" => $emparray) );
            }else{ 
                echo json_encode(array( "status" => "false","message" => "Invalid username or password!") );
            }
             mysqli_close($con);
     }
    } 
    else
    {
            echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
    }
?>

Java Code Welcome.java package com.exampledemo.sample.registerloginsession;

import android.content.Intent;
import android.content.res.Resources;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;

public class WelcomeActivity extends AppCompatActivity {

    private TextView tvname,tvmi_id;
    private Button btnlogout;
    private PreferenceHelper preferenceHelper;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_welcome);

        preferenceHelper = new PreferenceHelper(this);

        tvmi_id = (TextView) findViewById(R.id.tvmi_id);
        tvname = (TextView) findViewById(R.id.tvname);
        btnlogout = (Button) findViewById(R.id.btn);

        tvname.setText(preferenceHelper.getName());
        tvmi_id.setText(getResources().getString(R.string.welcome_message, preferenceHelper.getMi_id()));


        btnlogout.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                preferenceHelper.putIsLogin(false);
                Intent intent = new Intent(WelcomeActivity.this,See_Feedback.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
                startActivity(intent);
                WelcomeActivity.this.finish();
            }
        });

    }
}

Login.java
package com.exampledemo.sample.registerloginsession;

import android.content.Intent;
import android.content.res.Resources;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;

public class WelcomeActivity extends AppCompatActivity {

    private TextView tvname,tvmi_id;
    private Button btnlogout;
    private PreferenceHelper preferenceHelper;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_welcome);

        preferenceHelper = new PreferenceHelper(this);

        tvmi_id = (TextView) findViewById(R.id.tvmi_id);
        tvname = (TextView) findViewById(R.id.tvname);
        btnlogout = (Button) findViewById(R.id.btn);

        tvname.setText(preferenceHelper.getName());
        tvmi_id.setText(getResources().getString(R.string.welcome_message, preferenceHelper.getMi_id()));


        btnlogout.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                preferenceHelper.putIsLogin(false);
                Intent intent = new Intent(WelcomeActivity.this,See_Feedback.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK);
                startActivity(intent);
                WelcomeActivity.this.finish();
            }
        });

    }
}
  • 写回答

1条回答 默认 最新

  • 普通网友 2017-09-03 19:55
    关注

    Your code was poorly written; I tried to fix it.

    Please note that I strongly recommends the use of prepared statement to protect you against MySQL Injection

    Try this code below:

    <?php
        //Don't run code until POST request is received
       if($_SERVER['REQUEST_METHOD']=='POST'){
        include_once("dbConfig.php");
    
          //Extract content of POST request into variables $mi_id, $name
          $mi_id = isset($_POST['mi_id']) ? $_POST['mi_id'] : null;
          $name = isset($_POST['name']) ? $_POST['name'] : null;
    
         //Don't run next code if any of these variables 
         //is empty null or false; return message
         if( empty( $mi_id ) || empty( $name ) ){
                echo json_encode(array( "status" => "false","message" => "Parameter missing!") );
         }
    
        //If all you made it here, let's run the query; 
        $query= "SELECT * FROM registerdemo WHERE mi_id='$mi_id' AND name='$name'";
    
        //Only if there's result and greater than 0, then return something
        if( $result= mysqli_query($con, $query)) {
    
                if(mysqli_num_rows($result) > 0){  
                    $emparray = array();
                        while ($row = mysqli_fetch_assoc($result)!=NULL) {
                            $emparray[] = $row;
                        }
    
                    echo json_encode(array( "status" => "true","message" => "Login successfully!", "data" => $emparray) );
                }
                else{ 
                    echo json_encode(array( "status" => "false","message" => "Invalid username or password!") );
                }
        }
        else {
            echo json_encode(array( "status" => "false","message" => "Error occured, please try again!") );
        }
        // Close mysql connection;
         mysqli_close($con);
       }
    ?>
    

    Hope this helps.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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