doubo3384 2013-03-30 19:42
浏览 34
已采纳

如何从今天到过去的某个点获取一系列日期(特别是格式化)?

I would like to get an array containing strings like this: 2013-03, 2013-02, 2013-01, 2012-12, 2012-11... etc.

How would I go about it? I tried working with a loop and DateInterval class, but surprisingly 30.March -1month gives us 2.March, so that's not very useful.

$date = new DateTime();
$date->sub(DateInterval::createFromDateString('1 month'));

Thanks!

  • 写回答

1条回答 默认 最新

  • douyuan9512 2013-03-30 20:03
    关注

    Curiously, PHP returns the previous month of a date using the "next month" keyword :S

    You can do the following:

    <?php
    $date = new DateTime();
    // Subtract one month at a time
    // until we reach 2009.
    while ($date->format('Y') > 2009) {
        $date->sub(DateInterval::createFromDateString('next month'));
        var_dump($date->format('Y-m')); // Will print 2013-03 2013-02 [...]
    };
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 前端echarts坐标轴问题
  • ¥15 CMFCPropertyPage
  • ¥15 ad5933的I2C
  • ¥15 请问RTX4060的笔记本电脑可以训练yolov5模型吗?
  • ¥15 数学建模求思路及代码
  • ¥50 silvaco GaN HEMT有栅极场板的击穿电压仿真问题
  • ¥15 谁会P4语言啊,我想请教一下
  • ¥15 这个怎么改成直流激励源给加热电阻提供5a电流呀
  • ¥50 求解vmware的网络模式问题 别拿AI回答
  • ¥24 EFS加密后,在同一台电脑解密出错,证书界面找不到对应指纹的证书,未备份证书,求在原电脑解密的方法,可行即采纳