自定义数组排序

Question

At first - yes, I've tried to find my problem here, but can't make it.

I have a problem with array sorting. I want to use custom array sorting to sort some data taken from DB.

For example, I have array

values: [ 0, 0, 0, 0, 14830, 78426, 0, 0, 0, 0, 0, 0, 6024, 1144, 4438, 19282 ]

And I need to get last 4 (sometimes 3 or 2, so it would be custom) results on the first place in the same order as they are now. And the result should be like:

values: [ 6024, 1144, 4438, 19282, 14830, 78426, 0, 0, 0, 0, 0, 0,]

How can I do that?

I make this array with

while($row=mysql_fetch_array($re))
{
$dates = $row['mon'];

 while ($current_month != $dates) {
  $current_month = $current_month + 1;
  if($current_month == 13)
  $current_month = 1;
  $data[] = 0;
 }
 $data[] = intval($row['type']);
 $current_month = $dates+1;
}

I take months number as $current_month and using it puts my data in right places. When month have no results it adds 0 in that place. The results should be just 6 and when there's no passing through the years it makes array right, but sometimes it goes wrong like this, so I want to make proper array using custom sorting like I mantioned at first.

So I want to sort this array and with array_slice cut it to 6.

Thanks for help.

Answer 1

$desired_length = 4;
$arr = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14);
$length = count($arr);
$array = array_slice($arr, $length-$desired_length, $desired_length) + array_slice($arr,0,$length-$desired_length);